35x^2+6x-9=0

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Solution for 35x^2+6x-9=0 equation:



35x^2+6x-9=0
a = 35; b = 6; c = -9;
Δ = b2-4ac
Δ = 62-4·35·(-9)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-36}{2*35}=\frac{-42}{70} =-3/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+36}{2*35}=\frac{30}{70} =3/7 $

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